8x-7x^(1/2)=0

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Solution for 8x-7x^(1/2)=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

8*x-(7*x^(1/2)) = 0

8*x-7*x^(1/2) = 0

t_1 = x^(1/2)

8*t_1^2-7*t_1^1 = 0

8*t_1^2-7*t_1 = 0

DELTA = (-7)^2-(0*4*8)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+7)/(2*8) or t_1 = (7-49^(1/2))/(2*8)

t_1 = 7/8 or t_1 = 0

t_1 = 0

x^(1/2)+0 = 0

x^(1/2) = 0

1*x^(1/2) = 0 // : 1

x^(1/2) = 0

x = 0

t_1 = 7/8

x^(1/2)-7/8 = 0

1*x^(1/2) = 7/8 // : 1

x^(1/2) = 7/8

x^(1/2) = 7/8 // ^ 2

x = 49/64

x in { 0, 49/64 }

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